Name In Binary

Code:

package com.nearur;

import java.util.Scanner;

public class NTB {


static StringBuffer buffer=new StringBuffer();
public static void main(String[] args) {
Scanner in=new Scanner(System.in);
System.out.print("Enter Your Name:");
String a=in.nextLine();
String[] name=a.split(" ");

for(String x:name) {
convert(x);
}

System.out.println("Binary Code is : "+buffer.toString());
}

static void convert(String name) {

char[] a=name.toCharArray();
for(char x: a) {
binary((int)x);
buffer.append(" ");
}

}
static void binary(int n) {
while(n>0) {
if(n%2==0) {
buffer.append("0");
}else {
buffer.append("1");
}
n=n/2;
}
}


}

Output:

Computer Graphics (PUT PIXEL)

CODE:


#include<iostream.h>
#include<conio.h>
#include<graphics.h>
void main(){
int g=DETECT,gmode;
initgraph(&g,&gmode,"C://TURBOC3//BGI");
putpixel(100,100,10);
getch();
}


Output:

HangMan

Following Code is Hangman Like game without graphics inspired by Duta http:duta.in:


Code:

import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

public class Main {
static String check="AEIOU";
public static void main(String[] args) {
ArrayList<String> questions=new ArrayList<>();
questions.add("ABRUPTLY");
questions.add("BOOKWORM");
questions.add("GALAXY");
questions.add("PNEUMONIA");
questions.add("STRONGHOLD");
questions.add("WHIZZING");
questions.add("PUZZLING");
questions.add("WRISTWATCH");
questions.add("ZODIAC");
questions.add("THUMBSCREW");
questions.add("YACHTSMAN");
questions.add("MNEMONIC");
questions.add("TRANSPLANT");
questions.add("RHYTHM");
questions.add("MICROWAVE");
Collections.shuffle(questions);
String ques=questions.get(0);
   char[] given=new char[ques.length()];
   int count=0;
   for(int i=0;i<given.length;i++) {
    if(varcheck(ques.charAt(i))) {
    given[i]=ques.charAt(i);
    }else {
    given[i]='_';
    }
   }
   boolean win=false;
   Scanner in=new Scanner(System.in);
   StringBuffer buffer=new StringBuffer();
outer:
   while(count<7 && !win) {
    for(int i=0;i<given.length;i++) {
    System.out.print(given[i]+" ");
    }
    System.out.println();
    System.out.println("Guess a Letter");
    char c=in.nextLine().toUpperCase().charAt(0);
    int i=0;
    while(i<given.length) {
    if(given[i]==c) {
    System.out.println("Already Present in Word!!");
    System.out.println("Guessed Letters : "+buffer);
    System.out.println("Chances left : "+(7-count));
    System.out.println("------------------------------");
    continue outer;
    }i++;
    }
    if(buffer.toString().contains(c+"")) {
    System.out.println("Already Guessesed!!");
    System.out.println("Guessed Letters : "+buffer);
    System.out.println("Chances left : "+(7-count));
    System.out.println("------------------------------");
    continue outer;
    }
    if(ques.contains(c+"")) {
    int idx=ques.indexOf(c);
    while(idx>=0) {
    given[idx]=c;
    idx=ques.indexOf(c,idx+1);
    win=true;
    }
    System.out.println("Good Guess!!");
    }else {
    count++;
    System.out.println("Bad Guess!!");
    }
    buffer.append(c+",");
    System.out.println("Guessed Letters : "+buffer.toString().substring(0,buffer.length()-1));
    System.out.println("Chances left : "+(7-count));
    for(char x: given) {
    if(x=='_') {
    win=false;
    }
    }
    System.out.println("--------------------------------\n");
   }
    System.out.println("Word is : "+ques);
   if(win) {
    System.out.println("Congratulations,You win!!");
   }else {
    System.out.println("You Loose!!,Don't Worry Try Again");
   }
   in.close();
}
static boolean varcheck(char c) {
if(check.contains(c+"")) return true;
return false;
}

}

Output:

Desired Number of Quark Pairs

Following Code will give you desired number of quark pairs:


Code:

import java.util.Scanner;

public class MainQuark {
public static void main(String[] nt) {
System.out.print("Enter Value of N :");
int n;
Scanner in=new Scanner(System.in);
n=in.nextInt();
        int count=0,i=1,num;
        StringBuffer buffer=new StringBuffer();
while(count!=n) {
num=i;
int q=quark(num);
if(!prime(q)) {
for(int j=num+1;j<q;j++) {
if(q==quark(j)) {
buffer.append(i+"-"+j+"\n");
count++;
}
}
}
i++;
}
System.out.println("Pairs are\n"+buffer.toString());
}
static int quark(int n) {
int one=0,i=n;
while(n>0) {
if(n%2==1) {
one++;
}n=n/2;
}return one*(i);
}

static boolean prime(int n) {
for(int i=2;i<n/2;i++) {
if(n%i==0) return false;
}return true;
}

}

Output:

Quark Pairs Upto N

Quark Pairs: 

Code:

import java.util.Scanner;

public class MainQuark {

public static void main(String[] nt) {

System.out.print("Enter Value of N :");

int n;

Scanner in=new Scanner(System.in);

n=in.nextInt();

int[] quarks=new int[n];

int num=0;

for(int i=0;i<n;i++) {

num=i+1;

int one=0;

while(num>0) {

if(num%2==1) {

one++;

}num=num/2;

}

quarks[i]=one*(i+1);

}

StringBuffer buffer=new StringBuffer();

for(int i=0;i<n;i++) {

for(int j=i+1;j<n;j++) {

if(quarks[i]==quarks[j]) {

buffer.append((i+1)+"-"+(j+1)+"\n");

}

}

}

System.out.println("All Pairs upto "+n+" : ");

System.out.println(buffer.toString());

}

}

Output:

K-means Clustering

 What is K-means? 
1. Partitional clustering approach 
2. Each cluster is associated with a centroid (center point) 
3. Each point is assigned to the cluster with the closest centroid 
4 Number of clusters K must be specified 


Following Code will find the value of K :


Code:

Main.Java

import java.util.ArrayList;

import java.util.Collections;

public class Main {

   public static void main(String[] args) {
        long start=System.currentTimeMillis();
       int k=1;
      Point[] p=new Point[5];
      p[0]=new Point(1,1);
      p[1]=new Point(1,0);
      p[2]=new Point(0,2);
      p[3]=new Point(2,4);
      p[4]=new Point(3,5);
      
      ArrayList<Point> given=new ArrayList<>();
      given.add(p[0]);
      given.add(p[1]);
      given.add(p[2]);
      given.add(p[3]);
      given.add(p[4]);
      
      Collections.shuffle(given);
      Point c1=new Point(given.get(0));
      Point c2=new Point(given.get(1));


      ArrayList<Point>cluster1=new ArrayList<>();
      ArrayList<Point>cluster2=new ArrayList<>();

      ArrayList<Point>newcluster1=new ArrayList<>();
      ArrayList<Point>newcluster2=new ArrayList<>();

      double dc1,dc2;
      for(int i=0;i<5;i++) {
         dc1=c1.distance(p[i]);
         dc2=c2.distance(p[i]);
         if(dc1<dc2) {
            cluster1.add(p[i]);
         }else if(dc2<dc1) {
            cluster2.add(p[i]);
         }
      }
        c1.x=meanx(cluster1);
        c1.y=meany(cluster1);
        c2.x=meanx(cluster2);
        c2.y=meany(cluster2);
        do {
            if(!(newcluster1.isEmpty()&& newcluster2.isEmpty())) {
                cluster1.clear();
                System.out.println(cluster1.size());
                cluster1.addAll(newcluster1);
                cluster2.clear();
                cluster2.addAll(newcluster2);
                newcluster1.clear();
                newcluster2.clear();
            }
            for(int i=0;i<5;i++) {
                dc1=c1.distance(p[i]);
                dc2=c2.distance(p[i]);
                if(dc1<=dc2) {
                    newcluster1.add(p[i]);
                }else {
                    newcluster2.add(p[i]);
                }
            }
            c1.x=meanx(newcluster1);
            c1.y=meany(newcluster1);
            c2.x=meanx(newcluster2);
            c2.y=meany(newcluster2);
            k++;
        }while(!(compareCluster(cluster1, newcluster1)||compareCluster(cluster1, newcluster2))&&(compareCluster(cluster2, newcluster2)||compareCluster(cluster2, newcluster1)));
        System.out.println("Value of K is  : "+k);
      System.out.println("Time Taken : "+(System.currentTimeMillis()-start)+" milliseconds");
   }

    static boolean compareCluster(ArrayList<Point> c1,ArrayList<Point> c2) {
      if(c1.size()!=c2.size()||c1==null&&c2!=null||c1!=null&&c2==null) return false;
      if(c1==null && c2==null) return true;
      for(int i=0;i< c1.size();i++){
           if(! c2.contains(c1.get(i))) return false;
        }
        return true;
   }


   static double meanx(ArrayList<Point> c) {
      double sumx=0;
      for(int i=0;i<c.size();i++) {
         sumx+=c.get(i).x;
      }
      return sumx/c.size();
   }

    static double meany(ArrayList<Point> c) {
        double sumy=0;
        for(int i=0;i<c.size();i++) {
            sumy+=c.get(i).y;
        }
        return sumy/c.size();
    }
}

-------------------------------------------------------------------------------------------

Point.Java

public class Point {
   double x,y;
   
   Point(double a,double b){
      x=a;
      y=b;
   }
   Point(Point b){
      x=b.x;
      y=b.y;
   }
   
   double distance(Point b) {
      return Math.sqrt(Math.pow((x-b.x),2)+Math.pow((y-b.y),2));
   }

   @Override   public String toString() {
      return "Point [x=" + x + ", y=" + y + "]";
   }

}




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Output:

Happy Independence Day

Happy Independence Day in Programmers Style

Click here to see in real time